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    This dc voltage doubler circuit produces a voltage that is twice its voltage supply. This is useful when a higher voltage level is needed out of a single lower voltage power supply. Since the current consumption levels are low in such cases, the circuit can be built with minimal resources.

    Voltage Doubler Circuit Schematic

    555 voltage doubler circuit schematic

    The electronic circuit is basically a square wave generator using the common LM555 timer IC. It is followed by a final stage made of transistors T1 and T2. The actual doubler circuit is made of D1, D2, C4 and C5 components.

    The 555 dc voltage doubler timer IC works as an astable multivibrator and generates a frequency of about 8.5 kHz. The quare wave output drives the final stage made of T1 and T2. This is how the doubler works: by a low amplitude of the signal, transistor T1 blocks while T2 conducts. The minus electrode of the capacitor C4 is grounded and charges through D1. By a high amplitude of the signal, transistor T1 conducts while T2 blocks. However, capacitor C4 cannot discharge because it is blocked by D1. The following capacitor C5 is therefore charged with a combined voltage from C4 and the power supply (12V input).

    On standby, the circuit delivers around 20 volts. The maximum load must not exceed 70 mA. The actual output voltage is around 18 volts giving an efficiency rating of 32 %.
    On lower current ratings, the voltage is higher.
    If a stable voltage lever is desired, a 3 pin voltage regulator IC can be added at the output. The regulator IC’s own current consumption must be added to the total current consumption which must not exceed 70 mA.

    Diputado Johnson built a modified version of this circuit and posted some pictures on his website mobotgeek.blogspot.com. Here are some of them:

    For more voltage doublers check the related posts bellow.

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    44 Responses to "555 DC Voltage Doubler Circuit"

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    1. It works well although I built mine with an astable multivibrator. Watch the frequency and cap values.

    2. its not working when load is connected

    3. I am not able to get this to work. The voltage is acutally being cut in half. i am not sure what i am doing.

    4. OK its good I’m going to try it

    5. I have found that the CD4046 PLL a little more then the 555. use only the oscilator part of the chip. less parts needed and it will work up to 1 MHz.
      Tim

    6. Afdhal Atiff Tan says: on March 31, 2010 at 11:20 pm

      I failed to get higher voltage with transistors…

      Maybe its the forward voltage drop of those two transistor, I guess…

      I get better result with Mosfets…
      It was cold to touch too.

    7. is it compulsory to connect give 12v input or we can give other then 12?????

    8. my this circuit is not working

    9. venkatesh says: on January 5, 2011 at 3:33 pm

      What is the use of increasing frequency of ne555?
      Will increase in frequency increases out put watage at low voltages?
      Can we use this ckt in ups

    10. Zulker nien says: on January 9, 2011 at 4:44 pm

      What will be the change in the circuit when I double 6V to 10V?

    11. i want a detail of votage doubler circuit which was used in solar cell phone charger

    12. dragontirex says: on June 14, 2011 at 3:35 pm

      Well it gives me 20.8V when i connect 12V to it but once i hook up a load it drops but anyway i will try to tweak it, nice circuit :)

    13. hi,
      about the circuit you proposed above, then how the capacitor C5 is discharged? Many thanks for your help.

    14. jyothsna says: on July 27, 2011 at 1:00 pm

      i tried this as a mini project. thanks 4 ur help

    15. Required to convert a 6v 4.5Ah battery to 12v battery that can deliver at least 2amp current .please HELP!!!

    16. how can i get an exactly doubled value of the voltage from the voltage doubler ckt given above ..?

    17. can we modify it to get a negative voltage ie +12V and -12V? how?

      • Easy, just reverse the polarity of D1 and D2 as well as C4 and C5, and you will get approx -10 V at output instead of 20.

        Just did that myself yesterday ads I needed a negative voltage for supplying a op-amp.

      • Oh, forgot, you also need to move the connection of D1 to the ground wire instead of +12V..

    18. KABASHA says: on May 29, 2012 at 3:49 pm

      About the capacitor which doesn’t value,what value will we use? Help me.

    19. MUTHUSELVAM says: on June 25, 2012 at 8:48 am

      in this ckt, which factor is affecting the max current limit of 70 ma.plz help me & also thank for u

    20. mohandes says: on October 3, 2012 at 7:27 pm
        member

      i want to ask about function of

    21. Jim Keith Jim Keith says: on October 3, 2012 at 7:50 pm
        member

      C3 is an input 12V noise filter. It is non-critical and can be almost any value.

    22. Mihai says: on March 1, 2013 at 12:35 pm
        member

      Rezistorul R1(100Ω) este prea mic. E inadmisibil la LM555 ca rezistorul R1 să fie mai mic de 1KΩ. Este evident că pentru a obţine la ieşie(3) semnal cu factor de umplere(duty cycle) 0,5 e necersar ca R1 să fie ZERO, lucru imposibil. Tranzistorul de descărcare (pin 7) are limitare internă de curent dar nu şi de putere disipată. În schema de faţă prin pinul 7 se închide la masă(GND) un curent de aproape 120mA(dacă R1=100Ω), cu mult peste ceea ce poate tranz. de descărcare(pin3). Pentru obţinerea factorului de umplere de 0,5(practic 0,1…0,9) se poate face încărcarea şi descăcarea cond. C1 separat, cu două diode fără a stresa tranz. de descărcare. Vezi şi “AN170_NE555 and NE556 applications” (pdf).

    23. Johnson Diputado Johnson Diputado says: on April 16, 2013 at 7:17 pm
        member

      A very nice circuit. Just the right circuit for my motorcycle supply problem.

      My motorcycle electrical system can only output a maximum of 6V DC as it is an old Honda EX3 Malaysia MC. I wanted to install an LED strip as aesthetic lighting but it can only operate at 12v DC.

      Built a modified version of it as the NPN and PND transistor shown are not available here in my place and as well as the two 1N4002 rectifier diodes witn 1N4001s.

      Modified the 555 IC Based Generator Circuit from the basic Astable to the Astable with Diode so as make the Duty Cycle a perfect 50% (theoretically). R1 and R2 ar both 840Ohms and C1 to 0.1uF.

      Replaced the NPN transistor with 2N3904 while the PNP with 2N3906.

      The rest are of the same values.

      THIS CIRCUIT WORKS!!!!

      Found a similar description of this circuit at en.wikipedia.org under the name of “Diskson Multiplier” or “Dickson Charge Pump”.

      With this circuit my motorcycle could now operate a low ampere rating 12V device without having to modify its electrical system completely.

      • Can you send me some pictures of it? I want to publish them in this article and thank you for building this converter.

      • Johnson Diputado Johnson Diputado says: on April 19, 2013 at 3:24 pm
          member

        Hi :)

        I would be glad to. Please allow me a day to take the pictures of it . I’ll upload the pictures the moment I have them.

        Thank you…

      • Johnson Diputado Johnson Diputado says: on April 19, 2013 at 4:35 pm
          member

        By the way sir, should I send you the pics via an alternate email or through this site?

      • Simon John says: on August 7, 2013 at 2:01 pm
          member

        Please I want to to do this particular circuit for my mini project, any chance u could give me a help?

    24. Johnson Diputado Johnson Diputado says: on April 24, 2013 at 5:05 pm
        member

      The actual output voltage is closer to the theoretical output voltage is greater if the 1N4001 diode is replaced with 1N5818. This is due to the reason that the 1N5818 has a lesser threshold voltage than that of the 1N4001 diode which is 1V.

    25. kunal senjariya says: on August 3, 2013 at 6:01 am

      dear sir,

      can you provide me voltage doubler circuit diagram for 3v 60ma current.

    26. this circuit is good but what is its frequency range?

    27. annalarasu says: on August 26, 2013 at 7:58 pm

      sir
      the circuit is fine. i tried . when i give in put voltage of 5 volt dc it will not working. what can i do for it pl replay to my email. basically i am teacher in primary school. we r doing a project using windmill to charge the battery.

    28. himavanth says: on December 8, 2013 at 8:10 pm

      Hello sir , please give me details regarding the above circuit sir I want to increase my voltage without decrease in current I want to give input as 12volts 5amps and I need the volatge double or else upto 18volts but there should not be any decrease in the current. Please help me out sir.

    29. nishant says: on July 9, 2014 at 12:15 pm

      How can i get 20 volt 10 ampere output from this circuit???

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