IC 4060 Design Note

IC 4060 is an excellent integrated circuit for timing applications. Its ten active high outputs can give time delay from few seconds to hours. With a few components, it is easy to construct a simple but reliable time delay circuit.

IC 4060 is an Oscillator binary counter cum frequency divider. Its inbuilt oscillator is based on three inverters. The basic frequency of the internal oscillator is determined by the value of the capacitor connected to its pin 9 and that of the resistor in its pin 10. By increasing or decreasing the value of capacitor / resistor, time delay can be changed. Each output goes high after the completion of the timing cycle. To get maximum time period, output Q10 is omitted in the IC itself so that double time is available between Q9 and Q11.

Inside the IC, there is an oscillator and 14 series connected bistables (Ripple cascade arrangement). Internally the oscillator signal is applied to the first bistable which drives the second bistable and so on. Since each bistable divides its input signal by two, a total of fifteen signals are available, each of half the frequency of the previous one.

Ten of these fifteen signals are available on the output pins Q3- Q13.HEF 4060 is CMOS version which can operate at 3 volts while CD 4060 is high voltage type that can operate between 5 to 15 volts. It is necessary to add a capacitor close to pin 16 of IC so that minute voltage changes will not affect the timing cycle. Reset pin 12 resets the timing cycle once it is grounded. Outputs can give almost full supply voltage to drive light loads. Heavy loads such as relay can be operated through a driver transistor. When the high output is connected to the pin 11(clock input) through a diode, oscillation stops and IC remains latched in high state till it resets. Pin 11 can be used to give clock pulses from an external source.

4060 Timing cycle calculation

Time t = 2 n / f osc = Seconds

  • n is the selected Q output number
  • 2 n = Q output number = 2 x Q no times Eg. Q3 output = 2x2x2 = 8
  • f osc = 1 / 2.5 (R1xC1) = in Hertz

R1 is the resistor at pin 10 in Ohms and C1, the capacitor at pin 9 in Farads.

For example if R1 is 1M and C1 0.22, the basic frequency f osc is

1 / 2.5(1,000,000 x 0.000,000 22) = 1.8 Hz

If the selected output is Q3 then 2 n is 2 x 2 x 2 = 8

Therefore time period (in seconds) is

t = 2 n / 1.8 Hz = 8 / 1.8 = 4.4 seconds

A ready reckoner for selecting the output to get a required time delay is given along the diagram


Join the conversation!

Error! Please fill all fields.
  • AhmedAtta

    Hi friends
    i was try to use the ic 4060 in circuit wizard
    when i use the R = 1M and C = 0.4 iF The frequency should be 1
    But In Actual By Circuit Wizard make Different

  • prabu

    I am doing one project. In that project the light need to on 12hrs and also off 12hrs. How can I design the circuit. In which ic suitable for this… Help me


    the pin configuration you have given is different from it’s data sheet. ex:you have mentioned Q4-5th pin but,in data sheet Q4-7th pin. sir please do reply i am confused….thanks in advance.

  • abhishek

    sir i require a circuit that stops counting after 2.7 hours, designed from this 4060 ic itself. this repeats counting after the specified time does it not??

  • javier

    hi all. I have used the cd4060 IC in several circuits. I have arrived at the conclusion that it acts as a low frequency generator but I realized that duty cycle of the output pulses are always about 50%. is there a way to get CD4060 duty cyle to be between 70 and 90%??? say that a high state lasts 5 hours and the low state 2 hours…could this be obtained?

  • javier

    hi all. well I have used CD4060

  • chaitanya

    What about using IC 4010 instead of IC 4060

  • Thank u sir to giving information abt this project

    i have used my r1=150k and c= 0.1 micro n my freq is after calculation is 26.66 hz
    and time period is 0.3 sec howz it possible

  • Dinesh

    sir,This circuit give continuous time delay .i need a circuit when the time completed the circuit will totally turn off please sir.

    • Rajsekhar Nag

      You can use a diode from the output pin to one of the oscillator pin #11. This diode will act as a latching component, which will latch the IC once the set time lapses and the output of the IC goes high.

      Connect the cathode (band side) of a 1N4148 diode to the pin 11 and anode to the selected output pin.

      If this diode is not inserted, the output would go freewheeling from logic high to logic low and keep repeating the time delays.

      Also you can use a reset switch between pin 12 and 16.

  • shahul

    HI mohan,
    The circuit working fine.Excellent job.But i have problem.That The above circuit working in fine in BREADBOARD.But if it not working in the general purpose board.I checked all the connection.Its not working can U Just


Looking for the latest from TI?